Two Resistors 60 Ω Are Connected in Parallel and It’s Connected with a Cell of p.d 6 Volt. Find out the current through each resistors.
When two resistors 60 ohm connected in parallel are joined to a cell, the equivalent resistance, current, and related quantities can be easily found using standard formulas. This topic is often asked in Class 10, NEB, SEE, and CTEVT Physics exams.
Given
Two resistors each of resistance R = 60 Ω are connected in parallel and connected to a cell (details of cell EMF and internal resistance not shown in image). We will explain how to find the equivalent resistance of the parallel combination.
Step‑by‑Step Solution
For two resistors of the same value R in parallel, the equivalent resistance (R_eq) is given by:
R_eq = (R × R) / (R + R) = (60 × 60) / (60 + 60) = 3600 / 120 = 30 Ω
So, when two resistors 60 ohm connected in parallel, the equivalent resistance is 30 Ω. This makes the circuit draw more current than a single resistor.
In any parallel combination, the equivalent resistance is always less than the smallest individual resistance.
Two Resistors 60 Ω Are Connected in Parallel and It’s Connected with a Cell of p.d 6 Volt. Find out the current through each resistors.
Keywords
two resistors 60 ohm connected in parallel, equivalent resistance formula, parallel resistors, class 10 physics, NEB physics, SEE physics, CTEVT physics, electric circuits, resistance calculation, circuit problems, exam‐oriented physics, physics notes, Ohm’s law, current flow, parallel combination rules
Tags
resistors in parallel, equivalent resistance, electric circuit, class 10, NEB, SEE, CTEVT, physics problems, resistance calculation, parallel network, Ohm’s law, exam question, physics notes, aklearningnepal, education,Two Resistors 60 Ω Are Connected in Parallel and It’s Connected with a Cell of p.d 6 Volt. Find out the current through each resistors.
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Two Resistors 60 Ω Are Connected in Parallel and It’s Connected with a Cell of p.d 6 Volt. Find out the current through each resistors.