The Photoelectric Work Function of a Cesium Surface Is 4 eV – Explanation
the photoelectric work function of a cesium surface is 4 eV is a common numerical and conceptual question in modern physics. This is essential for Class 11, NEB, and CTEVT Physics exams.
What Is Work Function?
In the photoelectric effect, the work function is the minimum energy required to eject an electron from the metal surface. In this case, the photoelectric work function of a cesium surface is 4 eV.
Explanation
A work function of 4 eV means that each photon must have energy equal to or greater than 4 electron volts to eject electrons from a cesium surface. Since 1 eV equals 1.6 × 10-19 J, this work function corresponds to a threshold frequency and threshold wavelength for photoemission.
Cesium has a low work function, which makes it a suitable metal for observing photoelectric effects with visible light.
Exam Tip
When given the work function, you may be asked to find threshold frequency or threshold wavelength using Planck’s relation: E = hν and c = λν.
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Read related photoelectric effect questions here (Internal Link)
Keywords
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The Photoelectric Work Function of a Cesium Surface Is 4 eV