Find the Angle of Projection for Which Maximum Vertical Height and Horizontal Range are Equal (Power Guide)
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The complete explanation of projectile motion condition where maximum height and horizontal range become equal. In this guide, we will understand the required angle of projection, mathematical result and conceptual trick for fast remembering in exams.
What is the Condition?
This topic is extremely important in projectile motion. When a body is projected with initial velocity, both maximum height and range depend on the angle of projection. If both of these become equal, we must prove the required condition.
projectile motion angle equal height range Formula
Maximum Height (H) = (u² sin²θ) / (2g)
Horizontal Range (R) = (u² sin2θ) / g
projectile motion angle equal height range Condition Used
When H = R, the values become equal and after solving, we get the important angle.
Final Answer
Answer: The required angle of projection is θ = 45°
projectile motion angle equal height range Explanation
When the projectile is launched with angle forty five degrees the vertical and horizontal components balance the effect of gravity and motion, creating equal value of maximum height and horizontal distance. This result is directly useful in physics exams like SEE, Class 11, HA, and entrance preparation.
External Reference (DoFollow)
Google Search – Projectile Motion
Internal Links
Conclusion
Finally that the correct angle is 45°. This result is extremely useful in examinations and helps to understand standard projectile relations. Practice more numerical questions based on this concept for better score.
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