Two Resistors 60 Ω and 30 Ω Are Connected in Parallel and Connected With a Cell
When two resistors 60 and 30 ohm in parallel are connected with a cell, we can find the equivalent resistance of the circuit using parallel resistor formulas. This numerical is commonly asked in Class 10, NEB, SEE, and CTEVT Physics exams.
Given
Resistors: R₁ = 60 Ω and R₂ = 30 Ω
Connected in parallel and attached to a cell (details of cell EMF/internal resistance not shown).
Step-by-Step Solution
For resistors connected in parallel, the equivalent resistance R_eq is given by:
1/R_eq = 1/R₁ + 1/R₂ = 1/60 + 1/30
= 1/60 + 2/60 = 3/60
⇒ R_eq = 60/3 = 20 Ω
Therefore, when two resistors 60 and 30 ohm in parallel are connected, the net resistance of the combination is 20 Ω.
In parallel circuits, the equivalent resistance is always less than the smallest individual resistor.
parallel resistors 60 and 30 ohm
Keywords
two resistors 60 and 30 ohm in parallel, equivalent resistance calculation, parallel resistors, electric circuits, class 10 physics, NEB physics, SEE physics, CTEVT physics, Ohm’s law, resistor network, exam oriented physics, resistance problems, physics notes
Tags
resistors in parallel, equivalent resistance, electric circuit problems, class 10, NEB, SEE, CTEVT, physics numericals, Ohm’s law, network resistance, exam question, physics notes, aklearningnepal, education,parallel resistors 60 and 30 ohm
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parallel resistors 60 and 30 ohm