Calculate the Terminal Potential Difference Across a Circuit Having a Cell of EMF 6 V and Internal Resistance 0.9 Ω.
When we calculate terminal potential difference of a cell, we consider both the EMF of the cell and its internal resistance. This concept is essential for solving numerical problems in Class 10, NEB, SEE, and CTEVT Physics exams.
Given
EMF of cell, E = 6 V
Internal resistance, r = 0.2 Ω
(External resistance not shown in image — assume R or it may be given in full problem statement)
Concept
The terminal potential difference (V) of a cell is given by:
V = E − Ir
Here, I is the current flowing through the circuit and r is the internal resistance of the cell.
Terminal potential difference becomes less than EMF as current flows, due to energy loss in internal resistance.
Example Calculation
If we know the current (I) in the circuit, we substitute into V = E − Ir.
For instance, if external resistance is known, use Ohm’s law to find I first.
Calculate the Terminal Potential Difference Across a Circuit Having a Cell of EMF 6 V and Internal Resistance 0.9 Ω.
Keywords
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Tags
terminal potential difference, EMF, internal resistance, current electricity, physics numericals, Class 10, NEB, SEE, CTEVT, Ohm’s law, exam question, physics notes, aklearning, education,Calculate the Terminal Potential Difference Across a Circuit Having a Cell of EMF 6 V and Internal Resistance 0.9 Ω.
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Calculate the Terminal Potential Difference Across a Circuit Having a Cell of EMF 6 V and Internal Resistance 0.9 Ω.