What is the position of an image formed by a convex lens of focal length 18 cm when an object is placed 12 cm in the front of the lens?
To find the image position convex lens, we use the lens formula:
Lens Formula
1/f = 1/v − 1/u
Where,
f = focal length of the lens (18 cm),
u = object distance (−12 cm, since object is in front of the lens),
v = image distance (to be calculated)
Calculation
1/18 = 1/v − 1/(-12)
1/18 = 1/v + 1/12
1/v = 1/18 − 1/12
1/v = (2 − 3)/36
1/v = −1/36
v = −36 cm
Conclusion
The negative value of v indicates that the image is formed on the same side of the lens as the object. Hence, the image is virtual, erect, and magnified, located at 36 cm in front of the lens.
For convex lenses, when the object is placed between the focal point and the lens, the image formed is always virtual, erect, and magnified.
What is the position of an image formed by a convex lens of focal length 18 cm when an object is placed 12 cm in the front of the lens?
Keywords
image position convex lens, convex lens formula, focal length 18 cm, object distance 12 cm, virtual image, magnified image, Class 10 physics, NEB physics, SEE physics, CTEVT physics, lens numericals, physics exam question, lens calculation, physics notes, aklearningnepal
Tags
convex lens, image formation, virtual image, magnified image, lens formula, Class 10, NEB, SEE, CTEVT, physics notes, exam question, optics, focal length, object distance, aklearningnepal
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What is the position of an image formed by a convex lens of focal length 18 cm when an object is placed 12 cm in the front of the lens?